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📰 But $ d(t) = t^3 $ is strictly convex and has no minimum (it decreases on $ (-\infty, 0) $, increases on $ (0, \infty) $), so it does not achieve a minimum. However, the problem states that the **minimum depth is achieved exactly once**, which implies $ d(t) $ has a unique global minimum. But $ t^3 $ has no such minimum. Contradiction? 📰 Wait — unless our initial assumption that $ d(t) = t^3 $ is forced is correct, but it violates the minimum condition. So perhaps $ d(t) $ is not exactly $ t^3 $, but fits it at four points. But a cubic is uniquely determined by four points, so $ d(t) = t^3 $ is the only cubic polynomial satisfying the conditions. 📰 But $ d(t) = t^3 $ has no minimum. Unless minimum depth refers to **local minimum**? But still, $ t^3 $ has no local minimum. 📰 Secret Oig Exclusions Uncoveredrun This Check To Protect Your Rights 9296229 📰 Lisa Genshin Shocked Everyoneheres Her Secret That Will Blow Your Mind 4982608 📰 Cvs Just Unlocked A Secret Otc Sunshine Formula Click To Discover It Now 336173 📰 Upgrade To A Microsoft Refurbished Surface Pro Like New Affordable And Unbeatable 7115220 📰 Juan Carlos I 2788023 📰 Give Me Some Nyt 834125 📰 How A Single Side Kick Dominated Combat Sports Pure Genius 8540618 📰 Widgetsmith For Iphone 2894309 📰 David E Kelley Shows 6832207 📰 You Wont Believe What Happened When I Shared My Secrets 3979151 📰 Finally A Scooter With Seat That Makes Every Trip A Luxuryinside Secrets Youre Missing 9352304 📰 Now Try X 04 Y 05 Z 01 1169738 📰 Best Balance Transfer Cards No Transfer Fee 5829616 📰 Discover What The Powerful 999 Angel Number Reveals About Your Future 340235 📰 Usd To Gbp Exchange Rate Today You Could Lose 1200 In 24 Hours 8939442